Section 3
Practise questions
Question 1
Solve the following system of linear simultaneous equations: $$\qquad\, 2x + 2y = 2 \qquad\qquad(1)$$ $$4x + 6y + 3z = 1 \qquad\qquad(2)$$ $$\; -6x - 10y = -6 \qquad\qquad(3)$$
From equation (1), \(x=1-y\) is the expression for \(x\) in terms of \(y\).
Substitute \(1-y\) for \(x\) in equation (3):
$$-6(1 - y) - 10y = -6$$
$$\quad\; -6 + y - 10y = -6$$
$$\qquad\qquad\qquad y = 0$$
As, \(y=0\), from equation (1) we get \(x=1\) and from equation (2) we get \(z= -1\).
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